假设系统中互斥资源R的可用数为25。T0时刻进程P1、P2、P3、P4对资源R的最大需求数、已分配资源数和尚需资源数的情况如表a所示，若P1和P3分别申请资源R数为1和2，则系统()。表a T0时刻进程对资源的需求情况
- A.只能先给P1进行分配，因为分配后系统状态是安全的
- B.只能先给P3进行分配，因为分配后系统状态是安全的
- C.可以时后P1、P3进行分配，因为分配后系统状态是安全的
- D.不能给P3进行分配，因为分配后系统状态是不安全的
正确答案及解析
正确答案
解析
R的可用数初始为25，目前已经给4个进程分配出去6+4+7+6=23个资源，R剩余2个资源只能分配给尚需资源数最少的P3，使之可以顺利运行，分配后系统也是安全的。
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