PC1的IP地址为192.168.5.16，PC2的IP地址为192.168.5.100，PC1和PC2在同一网段中，其子网掩码可能是（ ）
- A.255.255.255.240
- B.255.255.255.224
- C.255.255.255.192
- D.255.255.255.128
正确答案及解析
正确答案
解析
本庭属于IP地址计算，根据题干PC1和PC2处在同一网段中，则说明这个子网规模至少包含了16-100之间的IP地址，也就是其子网规模至少要到的2的7次方，也就是128. 那对应的掩码第4个字节就可以使用256-128=128.因此对应的掩码就是255.255.255.128.
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