某进程有4个页面，页号为0~3，页面变换表及状态位、访问位和修改位的含义如下图所示。系统给该进程分配了3个存储块，当采用第二次机会页面替换算法时，若访问的页面1不在内存，这时应该淘汰的页号为（ ）。
- A.0
- B.1
- C.2
- D.3
正确答案及解析
正确答案
解析
本题的关键就是看懂这个图。本题3个存储块，4个页面。现在一开始3个存储块里面的页号是0、2、3.现在需要访问页号1，也就是把0、2、3中的一个替换出来，根据第二次机会算法。先看访问位，访问位一样的话，再看修改位。没有修改的页号3替换出来。所以答案是D。
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