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图甲是温度自动报警器。控制电路中,电源电压U=5V,热敏电阻R2的阻值与温度的关系如图乙所示:工作电路中,灯泡L标有“9V0.3A”的字样,R4为电子嗡鸣器,它的电流达到某一固定值时就会发声报警,其阻值R4=10Ω,在R2温度为20℃的情况下,小明依次进行如下操作:闭合开关S1和S2,灯泡L恰好正常发光,此时R0的电功率为P0;将R1的滑片调到最左端时,继电器的衔铁刚好被吸下,使动触点与下方静触点接触:调节R3的滑片,当R3与R4的电压之比U3:U4=4:1时,电子嗡鸣器恰好能发声,此时R0的电功率为P0′,P0′:P0=4:9,已知电源电压,灯丝电阻都不变,线圈电阻忽略不计,求:

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(1)灯泡L的额定功率;

(2)当衔铁刚好被吸下时,控制电路的电流;

(3)将报警温度设为50℃时,R1接入电路的阻值;

(4)工作电路的电源电压Ux

正确答案及解析

正确答案

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Saturday        29 May   image.png      

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