设机器码的长度为8，x为带符号纯小数，y为带符号纯整数，[X]原＝11111111，[Y]补＝11111111 ，则x的十进制真值为（），y的十进制真值为（）。
- A.–1
- B.127
- C.–127
- D.1
正确答案及解析
正确答案
解析
带符号的纯小数，符号位是看数字的第一位，0就是正的，1就是负的。正数的补码和原码都一样。而负数的补码是把原码除了符号位外全部取反再加上1。这道题x的原码就是1.1111111。然后再看小数点后1所在的位置n，根据公式y=（1/2）的n次方叠加就行了。这道题小数点后7位都是1，因此是
其结果是127/128，再加个负号，就得到x的十进制真值了：-127/128。
带符号纯整数，符号位是看数字的第一位，0就是正的，1就是负的。正数的补码和原码都一样。而负数的补码是把原码除了符号位外全部取反再加上1。这里[y]补=11111111，所以y的原码是10000001，则y的十进制真值是-1。
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