【函数2.1说明】
函数 int fun1(int m，int n)的功能是：计算并返回正整数m和n的最大公约数。
【函数2.2说明】
函数long fun2 ( char *str )的功能是：自左至右顺序取出非空字符串 str 中的数字字符形成一个十进制整数(最多8位)。例如：若字符串 str的值为“f3g8d5. ji2e3p12fkp”，则函数返回值为3852312。
【函数2.1】
int fun1(int m，int n)
{
while ( __（1）__ ) {
if (m>n) m=m-n;
else n=n-m;
}
___（2）___ ;
}
【函数2.2】
long fun2 ( char *str )
{
int i=0;
long k=0;
char *p=str;
while ( *p !=’\0’ && ___（3）___ ) {
if ( *p >= ’0’ && *p ＜= ‘9’ ) {
k = __（4）__ + *p – ‘0’ ;
++i;
}
___（5）___ ;
}
return k;
}
正确答案及解析
正确答案
解析
函数2.1：
（1） m ! =n ;
（2） return m; 或return n;
函数2.2：
（3） i＜8;
（4） k*10;
（5） p++
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