阅读以下说明和算法，完善算法并回答问题，将解答写在答题纸的对应栏内。
【说明】
假设以二维数组G[1. . m， 1. . n]表示一幅图像各像素的颜色，则G[i， j]表示区域中点（i，j）处的颜色，颜色值为0到k的整数。
下面的算法将指定点(i0， j0)所在的同色邻接区域的颜色置换为给定的颜色值。约定所有与点(i0， j0)同色的上、下、左、右可连通的点组成同色邻接区域。
例如，一幅8*9像素的图像如图1-1所示。设用户指定点（3，5），其颜色值为0，此时其上方(2，5)、下方(4，5)、右方(3，6)邻接点的颜色值都为0，因此这些点属于点(3，5)所在的同色邻接区域，再从上、下、左、右四个方向进行扩展，可得出该同色邻接区域的其他点（见图1-1中的阴影部分）。将上述同色区域的颜色替换为颜色值7所得的新图像如图1-2所示。
【算法】
输入：矩阵G，点的坐标（i0， j0），新颜色值newcolor。
输出：点（i0， j0）所在同色邻接区域的颜色置换为newcolor之后的矩阵G。
算法步骤（为规范算法，规定该算法只在第七步后结束）：
第一步：若点(i0， j0，)的颜色值与新颜色值newcolor相同，则 （1） ；
第二步：点（i0， j0）的颜色值→oldcolor;创建栈S，并将点坐标（i0，j0）入栈；
第三步：若 （2） ，则转第七步；
第四步：栈顶元素出栈－>(x， Y)，并 （3） ；
第五步：1）若点(x， y-1)在图像中且G[x， y-1]等于oldcolor，则（x， y-1）入栈S；
2）若点(x， y+1)在图像中且G[x， y+1]等于oldcolor，则（x， Y+ I）入栈S；
3）若点(x-1， y)在图像中且G[x-1， y]等于oldcolor，则（x-1， y）入栈S；
4）若点(x+1， y)在图像中且G[x+l， y]等于oldcolor，则（x+1， y）入栈S；
第六步：转 （4） ；
第七步：算法结束。
【问题】
是否可以将算法中的栈换成队列？回答： （5） 。
正确答案及解析
正确答案
解析
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