对n个关键码构成的序列采用简单选择排序法进行排序的过程是：第一趟经过n-1次关键码之间的比较，确定出最小关键码在序列中的位置后，再将其与序列的第一个关键码进行交换，第二趟则在其余的n-1个关键码中进行n-2次比较，确定出最小关键码的位置后，再将其与序列的第二个关键码进行交换……以此类推，直到序列的关键码从小到大有序排列。在简单选择排序过程中，关键码之间的总比较次数为（ ）。
- A.n（n-1）/2
- B.<img src='http://tp.mxqe.com/data/718/17975787_0.png' alt='中级软件评测师,历年真题,2019年下半年（上午）《软件评测师》真题' title='中级软件评测师,历年真题,2019年下半年（上午）《软件评测师》真题'>
- C.n（n+1）/2
- D.nlogn
正确答案及解析
正确答案
解析
依据题干的描述完成第1趟排序比较次数为n-1；第2趟为n-2次比较；以此类推；所以总的比较次数为：（n-1）+（n-2）+……+1=n（n-1）/2
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