若系统中有4个互斥资源R，当系统中有2个进程竞争R，且每个进程都需要i个R（i≤3）时，该系统可能会发生死锁的最小i值是（ ）。
- A.1
- B.2
- C.3
- D.4
正确答案及解析
正确答案
解析
当给每个进程都分配其所需资源数少1个资源，且还有1个剩余资源时，系统不会发生死锁。将本题中的数值带入上述公式中得：2*（i-1）+1＜=4，得出i＜=2.5，因此当i>=2.5时系统就可能会发生死锁，本题中选项C和选项D都符合要求，但本题需求i的最小值，因此正确选项应该选择C。
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