函数f和g的定义如下图所示。执行函数f时若采用引用（callbyreference）方式调用函数g（a），则函数f的返回值为（ ）。
- A.14
- B.18
- C.24
- D.28
正确答案及解析
正确答案
解析
本题采用引用调用，会改变实参的值。对于实参a，传递给g(a)之后，在g(a)函数，表现为形参x。
根据g(x)代码：m=5*2=10，x=10-1=9，返回值x+m=19；
返回f()代码，此时a（即g(x)中的x）的值已经改变，为9；c等于g(a)的返回值，也就是19。
最终可得f()的返回值a+c=28。
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