题目详情

已知算法A的运行时间函数为T(n)=8T(n/2)+n2,其中n表示问题的规模,则该算法的时间复杂度为(  )。另已知算法B的运行时间函数为T(n)=XT(n/4)+n2,其中n表示问题的规模。对充分大的n,若要算法B比算法A快,则X的最大值为(  )。
问题1选项
A.Θ(n)
B.Θ(nlgn)
C.Θ(n2)
D.Θ(n3)
问题2选项
A.15
B.17
C.63
D.65

正确答案及解析

正确答案
DC
解析
暂无解析

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